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- Solve the equation 3x + 5 = 17 | Wyzant Ask An Expert
3x + 5-5 = 17-5 2 This leaves you with just the 3x on the left and the number 12 on the right 3x = 12 3 Next you must divide both sides by 3 in order to get x by itself 3x 3 = 12 3 4 After dividing, you are left with x on the left and 4 on the right x=4 Therefore to solve the equation 3x + 5 = 17, replace x with 4
- 3x^2-17x+10 | Wyzant Ask An Expert
Factor of 30 will go and make 17 if you choose 15 and 2 So you can use = 3x^2 - 2x - 15x + 10 = x(3x - 2) -5(3x-2) = (3x-2)(x-5)
- Why does the equation y=3x+5 not represent a proportional . . . - Wyzant
Ask a question for free Get a free answer to a quick problem Most questions answered within 4 hours
- Solve the equation 3x+5y=15 for y | Wyzant Ask An Expert
3X + 5Y = 15 this is the equation you have to know how to solve for required variables here from the problem you have to solve for Y so, 3X + 5Y = 15 subtracting 3X from both sides, 3X + 5Y - 3X = 15 - 3X 5Y = 15 - 3X dividing both sides by 5 we get, Y = (15- 3X) 5
- equation :y=3x+7 what is the slope ,y intercept,and the lines are - Wyzant
The linear equation is given in slope-intercept form, y=mx + b Here, m is the slope, b is the y-intercept and (x,y) represent any point on the line or the ordered pair that makes the linear equation true
- For the function f defined by f (x) = 3x^2 - Wyzant
It seems like you already have the answers for parts A and B, so I will just work out part C f(x) = 3x^2 + 3x + 4
- Solve the congruence, 3x-=2(mod4) | Wyzant Ask An Expert
We attempt to isolate x in 3x ≡ 2(mod 4) While we cannot attempt to divide both sides by 3, the right side can be rewritten to give 3x = 4x - x ≡ 2(mod 4) Since 4x(mod 4) ≡ 0, we have-x ≡ 2(mod 4) We can now multiply both sides by -1 to get x ≡ -2(mod 4) Adding 4 to the right side to make it positive gives x ≡ 2(mod 4)
- Use the function f(x) to answer the questions: f(x) = 2x2 − 3x − 5
f(x) = 2x 2-3x -5 For Part A Set f(x) = 0 Factor the Quadratic Set the factors = 0 Solve each factor for x to find your x intercepts For Part B You need to use the coefficients in your Quadratic List them a = 2 , b = -3 and c = -5 Since a is positive, your parabola opens up Find the x coordinate of the vertex it is -b 2a
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