|
- self study - Probability of having 2 girls and probability of having at . . .
In this question the general formula P(A|B) = P(A ∩ B) P(B) is used I understand through intuition why the answer should be 1 3
- Expected number of ratio of girls vs boys birth
NumberOfChilden Probability Girls Boys 1 0 5 1 0 2 0 25 1 1 2 0 25 0 2 In this case the total expected children is more easily calculated Expected girls from one couple${}=0 5\cdot1 + 0 25\cdot1 =0 75$
- probability - What is the expected number of children until having at . . .
$\begingroup$ That can't be right, and you can see that by noting that the MINIMUM number of children is 2 If the expected number of children = the minimum number of children, it must be that there is no possibility of having more children than the minimum number - otherwise the expected number of children would be greater than the minimum number
- combinatorics - All combinations for a King and Queen (coed) 2s . . .
Ok so I have N girls and N guys I need to create a 2's beach volleyball coed tournament (also known as King and Queen style) I want a list (like Joe and Jill versus Donald and Melania etc ) of all possible unique games, given the following constraints: Coed 2's, so 2 members per team, 1 girl and 1 guy
- How to resolve the ambiguity in the Boy or Girl paradox?
The net effect is that even if I don't know which one is definitely a boy, the other child can only be a girl or a boy and that is always and only a 1 2 probability (ignoring any biological weighting that girls may represent 51% of births or whatever the reality is)
- probability - What is the expected number of children until having the . . .
You can consider starting from position 1 for the difference of boys girls and move up and down randomly with 50% probability until reaching zero These type of walks have been described here: What is the distribution of time's to ruin in the gambler's ruin problem (random walk)? and based on the results in those answers we can see that the
- Combinatorics - Arranging boys girls - Cross Validated
part (b) - the chances of a girls stand next to a boy is 1 the chances of a boy to stand next to a girl is 1 minus the chance not to stand next to a girl the answer is 1 - (answer from part 1) : 1 - 3 10 = 7 10 not sure this is the correct answer Thanks in advance for the help
- Hypothesis testing: Fishers exact test and Binomial test
The result obtained with the Fisher's exact test ("no significant difference between the proportion of girls and boys who finds that the cake tastes good") seems to contradict the results in (1) and (2), which say that the "more than 50% of the population of girls find that the cake tastes good" (1), and "no more than 50% of boys find that the
|
|
|