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- Expected number of ratio of girls vs boys birth
NumberOfChilden Probability Girls Boys 1 0 5 1 0 2 0 25 1 1 2 0 25 0 2 In this case the total expected children is more easily calculated Expected girls from one couple${}=0 5\cdot1 + 0 25\cdot1 =0 75$
- Combinatorics - Arranging boys girls - Cross Validated
part (b) - the chances of a girls stand next to a boy is 1 the chances of a boy to stand next to a girl is 1 minus the chance not to stand next to a girl the answer is 1 - (answer from part 1) : 1 - 3 10 = 7 10 not sure this is the correct answer Thanks in advance for the help
- self study - Probability of having 2 girls and probability of having at . . .
In this question the general formula P(A|B) = P(A ∩ B) P(B) is used I understand through intuition why the answer should be 1 3
- probability - What is the expected number of children until having the . . .
You can consider starting from position 1 for the difference of boys girls and move up and down randomly with 50% probability until reaching zero These type of walks have been described here: What is the distribution of time's to ruin in the gambler's ruin problem (random walk)? and based on the results in those answers we can see that the
- probability - What is the expected number of children until having at . . .
$\begingroup$ That can't be right, and you can see that by noting that the MINIMUM number of children is 2 If the expected number of children = the minimum number of children, it must be that there is no possibility of having more children than the minimum number - otherwise the expected number of children would be greater than the minimum number
- combinatorics - All combinations for a King and Queen (coed) 2s . . .
Ok so I have N girls and N guys I need to create a 2's beach volleyball coed tournament (also known as King and Queen style) I want a list (like Joe and Jill versus Donald and Melania etc ) of all possible unique games, given the following constraints: Coed 2's, so 2 members per team, 1 girl and 1 guy
- normal distribution - What is the probability that a girl is taller . . .
"Given that boys' heights are distributed normally $\mathcal{N}(68$ inches, $4 5$ inches$)$ and girls are distributed $\mathcal{N}(62$ inches, $3 2$ inches$)$, what is the probability that a girl chosen at random is taller than a boy chosen at random?"
- How to resolve the ambiguity in the Boy or Girl paradox?
The net effect is that even if I don't know which one is definitely a boy, the other child can only be a girl or a boy and that is always and only a 1 2 probability (ignoring any biological weighting that girls may represent 51% of births or whatever the reality is)
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