Irrationality of 0. 123456789101112 . . . and similar numbers Irrationality isn't hard, for any of them There are natural numbers with arbitrarily long strings of $1's$ or strings of $0's$, for example And, similarly, there are primes with such strings (there are infinitely many primes that start with any fixed sequence)
Remainder when $123456789101112\ldots$ is divided by $75$ How would you find the remainder when you divide $$1234567891011121314151617\\ldots201120122013$$ (The number formed by combining the numbers from $1$ to $2013$) by $75$?
prove 0. 1234567891011. . . is a normal number - Mathematics Stack Exchange Prove that 0 123456789101112 is normal So the number of times $1$ appear in the first $9$ digits after the decimal point is 1, then in the next $90$ digits is $19=10+1+8*1$, then the number of times $1$ appears in the next 900 digits is $100+19+19*8$
Electric Company - 1 2 3 4 5 6 7 8 9 10 11 12 - Reddit My husband and me 10 years apart in age both know this song I just introduced it to my 5 year old nephew He asked to hear "11 12" one more time before I flew back home
Efficient algorithm to find the n-th digit in the string . . . 112123123412345123456 123456789101112 Storing the entire string in memory is not feasible for very large n, so I am looking for an algorithm that can find the nth digit in the above string which works if n is very large (i e an alternative to just generating the first n digits of the string)
python - Concatenate the numbers between 1 and N and see if it is . . . Could you please clarify one section? You used N to mean two things, 12 and 123456789101112 First - if N is 12 and the output is 123456789101112 are you looking to see if 12 is divisible by 3 or if 123456789101112 is divisible by 3?