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K_ {sp} of salt A_3B_2, solubility x ,mol ,L^ {-1}, is: - Toppr
If x mol L−1 is the solubility of KAl(SO4)2, then Ksp is equal to:
1 mol of ferric oxalate is oxidized by x mol of - Toppr
1 mol of ferric oxalate is oxidised by x mol of M nO4− in acidic medium The ratio x y is :
1 mol of ferric oxalate is oxidised by x mol of Mn {O}_ {4 . . . - Toppr
16 x moles of potassium dichromate oxidises 1 mol of ferrous oxalate in acidic medium here x is
pK_a (CH_3 COOH) is 4. 74 . x mol of lead acetate and 0. 1 mol of . . . - Toppr
p K a (C H 3 C O O H) is 4 74 x mol of lead acetate and 0 1 mol of acetic acid in one L solution make a solution of p H = 5 04 Hence, x is -
If x mol L^ {-1} is the solubility of KAl (SO_ {4})_ {2}, then . . . - Toppr
The solubility of calcium phosphate in water is x mol L−1 at 25oC Its solubility product is equal to
Delta { U }^ { o } of combustion of methane is -X kJ { mol }^ { -1 . . .
ΔU o of combustion of methane is −X kJ mol−1 The value of ΔH o is:
Conductivity of 0. 00241 M acetic acid s 7. 896 x 10 - Toppr
Conductivity of 0 00241 M acetic acid s 7 896 x 10 −5 S cm, calculate its molar conductivity If λ ^ {0} m for acetic acid is 390 5 S cm 2 mol −1, what is its dissociation constant?
The conductivity of 0. 20 mol : L^ {-1} solution of KCl is 2. 48 . . . - Toppr
The conductivity of 0 20 m o l L − 1 solution of KCl is 2 48 × 10 − 3 S c m − 1 Calculate its molar conductivity and degree of dissociation ( α) Given λ 0 (K +) = 73 5 S c m 2 m o l − 1 and λ 0 (C l −) = 76 5 S c m 2 m o l − 1