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- 1 mol of ferric oxalate is oxidized by x mol of - Toppr
1 mol of ferric oxalate is oxidised by x mol of M nO4− in acidic medium The ratio x y is :
- K_ {sp} of salt A_3B_2, solubility x ,mol ,L^ {-1}, is: - Toppr
If x mol L−1 is the solubility of KAl(SO4)2, then Ksp is equal to:
- 1 mol of ferric oxalate is oxidised by x mol of Mn {O}_ {4 . . . - Toppr
16 x moles of potassium dichromate oxidises 1 mol of ferrous oxalate in acidic medium here x is
- 1 mol of ferric oxalate is oxidized by x mol of MnO^-_4 and 1 mol of . . .
1 mol of ferric oxalate is oxidised by x mol of M nO4− in acidic medium The ratio x y is :
- The concentration of oxalic acid is X mol lit^ {-1}. 40 mL of this . . .
The concentration of oxalic acid is ′X′ mol lit−1 40 mL of this solution reacts with 16 mL of 0 05 M acidified KM nO4 What is the pH of ′X′ M oxalic acid solution?
- 1 mol of ferric oxalate is oxidized by x mol of MnO . . . - Toppr
1 mol of ferric oxalate is oxidized by x mol of M nO⊝ 4 in acidic medium Hence, the value of x is: 1 2 1 6 1 8 1 5
- 1 mol each of H3PO2, H3PO3 and H3PO4 will neutralize x mole of . . . - Toppr
One mole each of H 3P O2, H 3P O3 and H 3P O4 will neutralize ' x ' mol of N aOH,'y' mol of Ca(OH)2 and 'z' mol of Al(OH)3 (assuming all to be strong electrolytes) respectively x,y and z are in the ratio:
- 1 mol of ferric oxalate is oxidised by xmol of {MnO_4}^- in . . . - Toppr
In acidic medium, two moles of permanganate oxidizes 5 moles of oxalic acid Also, 1 mole of permanganate oxidizes 5 moles of Fe (II) ions 1 mole of ferrous oxalate gives 1 mole of Fe (II) ions and 1 mole of oxalate ions It will require 1 5 moles of permanganate for the oxidation of Fe (II) ions and 2 5 moles of permanganate for the oxidation of oxalate ions Total permanganate required is 1
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