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- Question #8556c - Socratic
This means that the anilinium ion is a reasonably strong conjugate acid producing higher degree of hydrolytic effect than the Nitrite ion which => # [H^+] > [OH^-]# => pH < 7 (acidic)
- Question #c8170 - Socratic
Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O The basic equation is: Zn(OH)_2 + HCl to ZnCl_2 + H_2O if we balance the Chlorine atoms Zn(OH)_2 + 2HCl to ZnCl_2 + H_2O We now have to balance the oxygen atoms Zn(OH)_2 + 2HCl to ZnCl_2 + 2H_2O We now have the same number of each atoms of each element on each side of the equation
- Question #c76b8 - Socratic
Answer below Calcium oxide will dissolve to produce Calcium Hydroxide It is as follows: CaO + H_2O to Ca (OH)_2 In essence: "base + water" to "alkali"
- Question #c2681 - Socratic
The pH of the solution is 5 97 > The "NaOH" reacts with the "H"_2"PO"_4^"-" 0 460 color (red) (cancel (color (black) ("g NaOH"))) × "1 mol NaOH" (40 00 color (red
- Question #627ef - Socratic
functional groups like -OH, -CHO,-CO- are present in carbohydrates commonly two functional are present in a carbohydrate,-OH and -CHO, or -OH and-CO- Aldose shows different reactions and test like Tollen's silver mirror test, felling's test different types of reactions are also shown by carbohydrates like Osazone synthesis, length increasing reaction, oxidation reactions These are all due
- Question #22e51 - Socratic
Products formed are; Cu (OH)_2 + HCl -> CuCl_2 + H_2O Since CuCl_2 is soluble in water But; Cu (OH)_2 + HCl -> CuCl_2 + H_2O " [Not Balanced]" Balancing the equation
- Question #f2dad - Socratic
1 The yield will decrease; 2 There will be no effect on the yield > 1 Using 80 % propan-1-ol I'm guessing that you are making the propyl ester of a carboxylic acid and then titrating the reaction mixture to determine how much acid remains at the end of the esterification underbrace ("RCOOH")_color (red) ("carboxylic acid") + underbrace ("CH"_3"CH"_2"CH"_2"OH")_color (red) ("propan-1-ol
- Question #cebdb - Socratic
The resultant vector shows the plane moving 528 16 kph bearing 65 9 degrees I always like to sketch out an idea of what we're looking at Let's resolve the vectors and find the x and y components * * * * * * * * * * * * * * * * * * * * * * * Vector A 500 kph 60 degrees We can find the y component using sin (theta)= (opp) (hyp) Lucky for us, we have hyp, 500, and theta, 60 sin (60)= (opp) 500
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