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- SOLUTION: find value of: cos (2π 7)+cos (4π 7)+cos (6π 7)
You can put this solution on YOUR website! Answer: -1 2 Explanation Each term of cos (2pi 7)+cos (4pi 7)+cos (6pi 7) is of the form cos (2k*pi 7) where k is from the set {1,2,3} It might not be entirely obvious, but the expression cos (2k*pi 7) suggests we'll be using the nth roots of unity In this case n = 7 The roots of z^n = 1 are of the form cis (2k*pi n) cis is shorthand for "cosine i
- SOLUTION: Show that cos 2pi 9 is a root of the equation 8x^3 - 6x + 1=0
Question 1142053: Show that cos 2pi 9 is a root of the equation 8x^3 - 6x + 1=0 Found 2 solutions by math_helper, ikleyn:
- SOLUTION: Please help!!! If pi lt; theta lt; 2pi and cos theta= cos 1, what . . .
Question 973290: Please help!!! If pi < theta < 2pi and cos theta= cos 1, what is the value of theta? Round your answer to the nearest hundredth The answer is 5 28 but I do not know how to get that answer Please help!!! Thank you Answer by Boreal (15235) (Show Source):
- SOLUTION: Suppose that the height above ground of a person sitting on a . . .
You can put this solution on YOUR website! i think i have the answer, but i needed to graph the equation it in order to find it because it is a very confusing problem i changed t to x and graphed y = 18 8 - 16 7 * cos ( (2pi 5)*x) the graph is set to radians, since the angle is in radians the graph is shown below: when x is between 0 and 5, there are two points where the value of y is equal
- SOLUTION: 12. A sound wave is modeled with the equation y = 1 4 cos 2pi . . .
the normal period is 2pi in radians the equation of y = cos (x) is really y = cos (1*x) 1 is the frequency p = 2pi f becomes p = 2pi 1 which becomes p = 2pi when the frequency is 1, the period is 2pi the following graph of y = cos (x) shows that: in both cases, the cosine was starts at 1 and ends at 1 that's because cos (0) = 1 and cos
- SOLUTION: Please Help!! If pi lt;= theta lt; 2pi and cos (theta) = cos (1 . . .
Question 973278: Please Help!! If pi <= theta < 2pi and cos (theta) = cos (1), what is the value of theta? Answer by Edwin McCravy (20077) (Show Source):
- SOLUTION: If −𝜋 ≤ 𝑥 ≤ 0, then cos−1 (cos 𝑥) is: A)𝑥 B)𝜋−𝑥 C)2𝜋+𝑥 D)2𝜋−𝑥 . . .
Note cos (x) also takes on all its value on [-pi,0); but the convention is to use the interval where the numbers are positive cos (x) has a period of 2pi, so cos^ (-1) (cos (x)) returns a value equal to x, plus or minus the multiple of 2pi that makes the output value between 0 and pi
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