|
Canada-ON-CAMERON Azienda Directories
|
Azienda News:
- How do I round to exactly 2 decimal places in Python?
numb = 1 23456789123456789 print "num %0 2f" % numb then it'll display it as having only 2 decimal places num 1 23 but in reality the value for numb will remain the same How do I convert numb so that it will actually have the value of 1 23?
- MYSQL: function truncate(numeric,int) does not exist
CAST(152 23456789123456789 as DECIMAL(10, 1)) If you start with a floating point type, then the result is going to be floating point -- and the extra zeros are probably coming from that (however you are querying the data) Here is an example that shows the difference in types
- Using float type or double output a decimal number in Java(eclipse . . .
I wanted the output to be 0 123456789123456789 But, result is 0 123456789 in float type 0 12345678912345678 in double type So, I tried using %030 19f,e but this doesn't work either How do I out
- openxml - How does Excel show decimal values correctly although no . . .
It just limits input precision to 15 digits, e g try to put 25778 567889999955 in cell and see it is immediately converted (in Excel itself) to 25778 5678899999 and 1 23456789123456789 becomes 1 23456789123456 For more details on numeric representation internals and how it affects calculations see this wonderful wikipedia article
- ios - Xcode: App crashes because I deleted a class no other class uses . . .
xxx[98912:70b] 1 23456789123456789 - NSDecimalNumber xxx[98912:70b] 1 23456789123456789 - NSDecimalNumber as expected BUT you should still get rid of that NSDecimalNumber category Just put that code into it's own class Call it ZHNumberFormatter and do your formatting in there
- add method with two different array of integer objects
This test case should return 123456789123456789 Instead, it's returning 23456789123456789 I don't understand why 1 is not passing at the last index SIZE is a default static final value of 20 Can anyone help me with a bug?
- What is the relevance of M suffix on a decimal literal
decimal d = (decimal)1 23456789123456789; Console WriteLine(d); Prints 1 23456789123457 decimal e = 1 23456789123456789M; Console WriteLine(e); Prints 1 23456789123456789 Note that the following will compile without a suffix or a cast, because int to decimal conversion never loses precision: decimal l = 50;
- python - int () от большого числа не правильно работает - Stack . . .
123456789123456784 123456789123456789 1 23456789123456789e+17 123456789123456789 0 Таким образом, встроенный float питона изначально не способен такую точность поддерживать Варианты решения проблемы: использовать изначально int
- Parsear un número bastante grande java - Stack Overflow en español
Tengo el siguiente problema: quiero guardar el número 123456789123456789 en una base de datos, pero el valor almacenado no es exacto: println params randomQuantitative println quot;Double: quot; +
- Recently Active truncate Questions - Page 6 - Stack Overflow
Stack Overflow | The World’s Largest Online Community for Developers
|
|